325=a^2

Solution for 325=a^2 equation:

325=a^2

We move all terms to the left:

325-(a^2)=0

We add all the numbers together, and all the variables

-1a^2+325=0

a = -1; b = 0; c = +325;
Δ = b2-4ac
Δ = 02-4·(-1)·325
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{13}}{2*-1}=\frac{0-10\sqrt{13}}{-2}
=-\frac{10\sqrt{13}}{-2}
=-\frac{5\sqrt{13}}{-1}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{13}}{2*-1}=\frac{0+10\sqrt{13}}{-2}
=\frac{10\sqrt{13}}{-2}
=\frac{5\sqrt{13}}{-1}
$